document.write( "Question 872883: Find the equation of the lines which are tangent to the circle x^2+y^2=625 & perpendicular to the line 24x-7y+84=0 \n" ); document.write( "
Algebra.Com's Answer #526511 by Alan3354(69443)\"\" \"About 
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Find the equation of the lines which are tangent to the circle x^2+y^2=625 & perpendicular to the line 24x-7y+84=0
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\n" ); document.write( "m, the slope of 24x-7y+84=0 is 24/7
\n" ); document.write( "The slope perpendicular = -7/24
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\n" ); document.write( "The slope at any point on a circle about the Origin is -x/y
\n" ); document.write( "-7/24 = -x/y
\n" ); document.write( "7y = 24x --> y = 24x/7
\n" ); document.write( "x^2+y^2=625
\n" ); document.write( "x^2 + (576x^2/49) = 625
\n" ); document.write( "49x^2 + 576x^2 = 30625
\n" ); document.write( "625x^2 = 30625
\n" ); document.write( "x^2 = 49
\n" ); document.write( "x = 7, y = 24
\n" ); document.write( "x = -7, y = -24
\n" ); document.write( "Use the points and the slope (-7/24) to find the eqns of the 2 lines.
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