document.write( "Question 872880: An airplane flew for 3 hours with a 20mph tail wind. The return flight against the same wind took 4 hours. Find the speed of the plane in still air.
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Algebra.Com's Answer #526496 by mananth(16946)![]() ![]() You can put this solution on YOUR website! plane speed x mph \n" ); document.write( "wind speed 20 mph \n" ); document.write( ".. \n" ); document.write( "against wind x- 20 \n" ); document.write( "with wind x+ 20 \n" ); document.write( ".. \n" ); document.write( "against wind 4 hours \n" ); document.write( "with wind 3 hours \n" ); document.write( "Distance is same. D=r*t \n" ); document.write( "4 ( x - 20 ) = 3 ( x + 20 ) \n" ); document.write( "4 x - 80 = 3 x + 60 \n" ); document.write( "4 x - 3 x = 80 + 60 \n" ); document.write( "1 x = 140 \n" ); document.write( "/ 1 \n" ); document.write( "x = 140 mph \n" ); document.write( "plane speed = 140 mph \n" ); document.write( " \n" ); document.write( " |