document.write( "Question 872872: A trader bought paraffin for $500. He paid $x for each litre.
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document.write( "a) Due to a leak he lost 3 litres of paraffin. He sold the remainder for $1 per liter more than he paid for it. Write an experession in terms of x for his total income.
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document.write( "B) He made a $20 profit. Write and solve the equation which represents this information.
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document.write( "c) How many litres of paraffin did he sell?\r
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document.write( "I know that 500/x is the amount of litres he bought, so is the remaining amount. I don't know what to do next, is the remaining amount multiplied by (x+1)? \n" );
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Algebra.Com's Answer #526490 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A trader bought paraffin for $500. He paid $x for each litre.\r \n" ); document.write( "\n" ); document.write( "Number of litres he bought = 500/x\r \n" ); document.write( "\n" ); document.write( "a) Due to a leak he lost 3 litres of paraffin.\r \n" ); document.write( "\n" ); document.write( "balance = (500/x) -3 \r \n" ); document.write( "\n" ); document.write( "He sold the remainder for $1 per liter more than he paid for it.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Profit = \n" ); document.write( " \n" ); document.write( " Write an expression in terms of x for his total income.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "B) He made a $20 profit.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "c) How many litres of paraffin did he sell?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "mulyiply by \n" ); document.write( "(500-3x)(x+1) =520x\r \n" ); document.write( "\n" ); document.write( "500x+500-3x^2-3x=520x\r \n" ); document.write( "\n" ); document.write( "3x^2+23x-500=0\r \n" ); document.write( "\n" ); document.write( "solve \r \n" ); document.write( "\n" ); document.write( "a= 3 , b= 23 , c= -500 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 529 + 6000 \n" ); document.write( "b^2-4ac= 6529 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( -23 + 80.8 )/ 6 \n" ); document.write( "x1= 9.63 \n" ); document.write( " \n" ); document.write( "x2=( -23 -80.8 ) / 6 \n" ); document.write( "x2= -17.30 \n" ); document.write( "Ignore negative value \n" ); document.write( "cost per litre = 9.63 \n" ); document.write( "that works out to 51.92 litres\r \n" ); document.write( "\n" ); document.write( "he sold 48.92 litres @ 10.63\r \n" ); document.write( "\n" ); document.write( "= 520.02 \n" ); document.write( " |