document.write( "Question 872872: A trader bought paraffin for $500. He paid $x for each litre.
\n" ); document.write( "a) Due to a leak he lost 3 litres of paraffin. He sold the remainder for $1 per liter more than he paid for it. Write an experession in terms of x for his total income.
\n" ); document.write( "B) He made a $20 profit. Write and solve the equation which represents this information.
\n" ); document.write( "c) How many litres of paraffin did he sell?\r
\n" ); document.write( "\n" ); document.write( "I know that 500/x is the amount of litres he bought, so \"500%2Fx+-3\" is the remaining amount. I don't know what to do next, is the remaining amount multiplied by (x+1)?
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Algebra.Com's Answer #526490 by mananth(16946)\"\" \"About 
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A trader bought paraffin for $500. He paid $x for each litre.\r
\n" ); document.write( "\n" ); document.write( "Number of litres he bought = 500/x\r
\n" ); document.write( "\n" ); document.write( "a) Due to a leak he lost 3 litres of paraffin.\r
\n" ); document.write( "\n" ); document.write( "balance = (500/x) -3 \r
\n" ); document.write( "\n" ); document.write( "He sold the remainder for $1 per liter more than he paid for it.\r
\n" ); document.write( "\n" ); document.write( "\"%28%28500%2Fx%29-3%29%28x%2B1%29\" = total sales\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Profit =\"%28%28500%2Fx%29-3%29%28x%2B1%29-500\"
\n" ); document.write( "
\n" ); document.write( " Write an expression in terms of x for his total income.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "B) He made a $20 profit.\r
\n" ); document.write( "\n" ); document.write( "\"%28%28500%2Fx%29-3%29%28x%2B1%29-500\"=20
\n" ); document.write( "
\n" ); document.write( "c) How many litres of paraffin did he sell?\r
\n" ); document.write( "\n" ); document.write( "\"%28%28500%2Fx%29-3%29%28x%2B1%29=520\"\r
\n" ); document.write( "\n" ); document.write( "mulyiply by
\n" ); document.write( "(500-3x)(x+1) =520x\r
\n" ); document.write( "\n" ); document.write( "500x+500-3x^2-3x=520x\r
\n" ); document.write( "\n" ); document.write( "3x^2+23x-500=0\r
\n" ); document.write( "\n" ); document.write( "solve \r
\n" ); document.write( "\n" ); document.write( "a= 3 , b= 23 , c= -500
\n" ); document.write( "
\n" ); document.write( "b^2-4ac= 529 + 6000
\n" ); document.write( "b^2-4ac= 6529
\n" ); document.write( "\"%09sqrt%28%096529%09%29=%0980.8%09\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( -23 + 80.8 )/ 6
\n" ); document.write( "x1= 9.63
\n" ); document.write( "\"x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x2=( -23 -80.8 ) / 6
\n" ); document.write( "x2= -17.30
\n" ); document.write( "Ignore negative value
\n" ); document.write( "cost per litre = 9.63
\n" ); document.write( "that works out to 51.92 litres\r
\n" ); document.write( "\n" ); document.write( "he sold 48.92 litres @ 10.63\r
\n" ); document.write( "\n" ); document.write( "= 520.02
\n" ); document.write( "
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