document.write( "Question 872851: A recent survey shows that 60% of the factory workers willing to work overtime
\n" ); document.write( "without extra pay as long as they are guaranteed job security and bonus at the
\n" ); document.write( "end of the year. Fifteen factory workers are randomly selected, find (Use binomial
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\n" ); document.write( "(a) The mean and standard deviation of the number of workers who are willing to
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\n" ); document.write( "(b) The probability that at least 13 workers are willing to work overtime without
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\n" ); document.write( "(c) The probability that 10 workers are unwilling to work overtime without extra
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\n" ); document.write( "(d) Explain why a binomial distribution is suitable for computing probabilities of
\n" ); document.write( "the number of workers who are willing to work overtime without pay. (3 marks) \n" ); document.write( "

Algebra.Com's Answer #526479 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "p(willing to work overtime without pay) = .6,  n = 15
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document.write( "a) Mean = .6*15 = 9, sd = √9 = 3
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document.write( "b) P(x ≥ 13) =   1 - binomcdf(15, .6, 12) = .0271
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document.write( "c) P(x=10) = 15C10(.6)^10(.4)^4   0r  binompdf(15, .6, 10)= .1859
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document.write( "Single x-value
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document.write( "p and q are the probabilities of success and failure respectively. 
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document.write( "In this case p = .6 & q = .4
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