document.write( "Question 872853: Please help me solve this induction question using a direct proof:
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document.write( "Prove by induction that n! < n^n, for positive integers n >= 2 \n" );
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Algebra.Com's Answer #526474 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! First prove the base case n = 2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n! < n^n \n" ); document.write( "2! < 2^2 \n" ); document.write( "2 < 4 ... true\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Inductive Step:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Assume the n = k case is true. So assume\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "k! < k^k\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "is true. We must prove the n = k+1 case is true based on the assumption n = k.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So start with k! < k^k and multiply both sides by k+1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "k! < k^k \n" ); document.write( "(k+1)*k! < (k+1)*k^k\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The inequality is still true because k+1 is positive (n >= 2, so k > 2). So the inequality sign has NOT flipped. It only flips when we multiply both sides by a negative number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now if we replace the base 'k', of k^k on the right side, with 'k+1', we get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(k+1)*k! < (k+1)*k^k \n" ); document.write( "(k+1)*k! < (k+1)*(k+1)^k \n" ); document.write( "(k+1)*k! < (k+1)^1*(k+1)^k \n" ); document.write( "(k+1)*k! < (k+1)^(1+k) \n" ); document.write( "(k+1)*k! < (k+1)^(k+1) \n" ); document.write( "(k+1)! < (k+1)^(k+1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This last inequality is certainly true because (k+1)*k! < (k+1)*k^k is true and (k+1)^k is larger than k^k. \n" ); document.write( "That means (k+1)*(k+1)^k is larger than (k+1)*k^k. \n" ); document.write( "By extension, this means (k+1)*(k+1)^k is larger than (k+1)*k! \n" ); document.write( "So the right side is still larger than the left side. That's all we care about.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So to wrap things up we assumed the equation held true for the n = k case. Then we just showed that the n = k+1 case is true based on the assumption that the inequality holds true when n = k. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This inductive step proves n! < n^n is true for all integers n >= 2. \n" ); document.write( " \n" ); document.write( " |