document.write( "Question 872831: If cot A = 4/3, with A in Q3, Find sec 2A. \n" ); document.write( "
Algebra.Com's Answer #526469 by lwsshak3(11628) ![]() You can put this solution on YOUR website! If cot A = 4/3, with A in Q3, Find sec 2A. \n" ); document.write( "You are working with a (3-4-5) reference right triangle in Q3 in which sin<0, cos<0 \n" ); document.write( "cos A=-4/5 \n" ); document.write( "sin A=-3/5 \n" ); document.write( "cos 2A=cos^2A-sin^2A=16/25-9/25=7/25 \n" ); document.write( "sec 2A=1/cos 2A=25/7 \n" ); document.write( ".. \n" ); document.write( "calculator check: \n" ); document.write( "cos A=-4/5 \n" ); document.write( "A≈216.87˚ \n" ); document.write( "2A≈433.74 \n" ); document.write( "cos 2A≈cos(433.74)≈0.2799… \n" ); document.write( "Exact value=7/25≈0.28 \n" ); document.write( " \n" ); document.write( " |