document.write( "Question 872831: If cot A = 4/3, with A in Q3, Find sec 2A. \n" ); document.write( "
Algebra.Com's Answer #526469 by lwsshak3(11628)\"\" \"About 
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If cot A = 4/3, with A in Q3, Find sec 2A.
\n" ); document.write( "You are working with a (3-4-5) reference right triangle in Q3 in which sin<0, cos<0
\n" ); document.write( "cos A=-4/5
\n" ); document.write( "sin A=-3/5
\n" ); document.write( "cos 2A=cos^2A-sin^2A=16/25-9/25=7/25
\n" ); document.write( "sec 2A=1/cos 2A=25/7
\n" ); document.write( "..
\n" ); document.write( "calculator check:
\n" ); document.write( "cos A=-4/5
\n" ); document.write( "A≈216.87˚
\n" ); document.write( "2A≈433.74
\n" ); document.write( "cos 2A≈cos(433.74)≈0.2799…
\n" ); document.write( "Exact value=7/25≈0.28
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