document.write( "Question 73624: The question says solve:
\n" ); document.write( "x(x+1)= -2(x-4)=2
\n" ); document.write( "This is what I did, can you tell me if I am on the right track, please?
\n" ); document.write( "x(x+1)= -2(x-4)=2
\n" ); document.write( "x*2+1x= -2x+8+2
\n" ); document.write( "x*2+x+2x-8-2=0
\n" ); document.write( "x*2+3-10=0
\n" ); document.write( "(x+5) (x-2)
\n" ); document.write( "x+5=0 x-2=0
\n" ); document.write( "x=-5 and x=-2
\n" ); document.write( "

Algebra.Com's Answer #52646 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, there are a couple of discrepancies I see here.
\n" ); document.write( "1) Although your first equation is written as:
\n" ); document.write( "x(x+1)=-2(x-4)=2, I assume that there is a typo and that you meant to write:
\n" ); document.write( "\"x%28x%2B1%29+=+-2%28x-4%29%2B2\" Right?
\n" ); document.write( "The second thing that I notice is that you have not handled the (+ & -) signs correctly. Let's step through the process:
\n" ); document.write( "\"x%28x%2B1%29+=+-2%28x-4%29%2B2\" Apply the distributive property to both sides.
\n" ); document.write( "\"x%5E2%2Bx+=+-2x%2B8%2B2\" Combine like-terms.
\n" ); document.write( "\"x%5E2%2B3x+=+10\" Subtract 10 from both sides.
\n" ); document.write( "\"x%5E2%2B3x-10+=+0\" Factor this quadratic equation.
\n" ); document.write( "\"%28x-2%29%28x%2B5%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"x-2+=+0\" and/or \"x%2B5+=+0\"
\n" ); document.write( "Solutions:
\n" ); document.write( "x = 2 or x = -5
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