document.write( "Question 872841: Ok, this one is killing me, I guess I just can't wrap my head around it. Tired of trying and failing to get it. Given: Triangle ACB is Isosceles with a base of segment AC. There is a segment running from B to the base ending at D(not stated as a given, but is drawn). Given: Angle CBD is congruent to Angle ABD. Prove: D is the midpoint of segment AC. I have tried to write the two column proof and have no confidence I am doing anything write. This is the last homework question I have to complete for this semester. Any help with this is greatly appreciated. \n" ); document.write( "
Algebra.Com's Answer #526457 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
In triangles CBD & ABD\r
\n" ); document.write( "\n" ); document.write( "angle CBD is congruent to angle ABD
\n" ); document.write( "side BC is congruent to side AB ( isosceles triangle)
\n" ); document.write( "AD is the common side\r
\n" ); document.write( "\n" ); document.write( "so the triangles are congruent\r
\n" ); document.write( "\n" ); document.write( "there fore AD = DC\r
\n" ); document.write( "\n" ); document.write( "therefore D is the mid point of AC\r
\n" ); document.write( "\n" ); document.write( "----------------\r
\n" ); document.write( "\n" ); document.write( "OR you can also prove by angular bisector theorem\r
\n" ); document.write( "\n" ); document.write( "BD is the angular bisector of angle C
\n" ); document.write( "AC=BC\r
\n" ); document.write( "\n" ); document.write( "D is any point on the angular bisector of angle C\r
\n" ); document.write( "\n" ); document.write( "Any point on the angular bisector of and angle is equidistant from the endpoints of the sides of the angle contained by them\r
\n" ); document.write( "\n" ); document.write( "therefore D is the mid point of AB\r
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