document.write( "Question 872841: Ok, this one is killing me, I guess I just can't wrap my head around it. Tired of trying and failing to get it. Given: Triangle ACB is Isosceles with a base of segment AC. There is a segment running from B to the base ending at D(not stated as a given, but is drawn). Given: Angle CBD is congruent to Angle ABD. Prove: D is the midpoint of segment AC. I have tried to write the two column proof and have no confidence I am doing anything write. This is the last homework question I have to complete for this semester. Any help with this is greatly appreciated. \n" ); document.write( "
Algebra.Com's Answer #526457 by mananth(16946)![]() ![]() You can put this solution on YOUR website! In triangles CBD & ABD\r \n" ); document.write( "\n" ); document.write( "angle CBD is congruent to angle ABD \n" ); document.write( "side BC is congruent to side AB ( isosceles triangle) \n" ); document.write( "AD is the common side\r \n" ); document.write( "\n" ); document.write( "so the triangles are congruent\r \n" ); document.write( "\n" ); document.write( "there fore AD = DC\r \n" ); document.write( "\n" ); document.write( "therefore D is the mid point of AC\r \n" ); document.write( "\n" ); document.write( "----------------\r \n" ); document.write( "\n" ); document.write( "OR you can also prove by angular bisector theorem\r \n" ); document.write( "\n" ); document.write( "BD is the angular bisector of angle C \n" ); document.write( "AC=BC\r \n" ); document.write( "\n" ); document.write( "D is any point on the angular bisector of angle C\r \n" ); document.write( "\n" ); document.write( "Any point on the angular bisector of and angle is equidistant from the endpoints of the sides of the angle contained by them\r \n" ); document.write( "\n" ); document.write( "therefore D is the mid point of AB\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |