document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=872813>Question 872813</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the exact values of the six trigonometric functions of t if p= (-1/3, 2 square root of 2 over 3) is the point on the unit circle that corresponds to t </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526445 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the exact values of the six trigonometric functions of t if p= (-1/3, 2 square root of 2 over 3) is the point on the unit circle that corresponds to t<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "x = -1/3<BR>\n" );
document.write( "y = 2sqrt(2)/3<BR>\n" );
document.write( "---<BR>\n" );
document.write( "r = sqrt[(1/3)^2 + (2sqrt(2)/3)^2] = sqrt[(1/9)+(8/9)] = 1<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "sin = x/r = -1/3<BR>\n" );
document.write( "cos = y/r = 2sqrt(2)/3<BR>\n" );
document.write( "tan = y/x = -1/2sqrt(2)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "csc, sec, and cot are the inverse of sin, cos, and tan<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=================<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );