document.write( "Question 73620: The following problem is not from a book.
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document.write( "Jose has 6 more dimes than quaters. If his coins total $ 1.65. How many coins of each type does he have. My solution is 3 quaters and 9 dimes. However I can not put it into an equation.\r
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Algebra.Com's Answer #52644 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let D = the number of dimes ($0.10) and Q = the number of quarters ($0.25). \n" ); document.write( "Jose has 6 more dimes than quarters. This can be written: \n" ); document.write( "D = Q+6 \n" ); document.write( "The total amount of money is $1.65. This can be written: \n" ); document.write( "($0.10)D+($0.25)Q = $1.65 Now substitute the first equation for D here. \n" ); document.write( "($0.10)(Q+6)+($0.25)Q = $1.65 Simplify and solve for Q. \n" ); document.write( "($0.10)Q + $0.60 + ($0.25)Q = $1.65 Combine like-terms. \n" ); document.write( "($0.35)Q + $0.60 = $1.65 Subtract $0.60 from both sides. \n" ); document.write( "($0.35)Q = $1.05 Divide both sides by ($0.35) \n" ); document.write( "Q = 3 This is the number of quarters Jose has. \n" ); document.write( "D = Q+6 \n" ); document.write( "D = 3+6 = 9 This is the number of dimes Jose has. \n" ); document.write( " \n" ); document.write( " |