document.write( "Question 73620: The following problem is not from a book.
\n" ); document.write( "Jose has 6 more dimes than quaters. If his coins total $ 1.65. How many coins of each type does he have. My solution is 3 quaters and 9 dimes. However I can not put it into an equation.\r
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Algebra.Com's Answer #52644 by Earlsdon(6294)\"\" \"About 
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Let D = the number of dimes ($0.10) and Q = the number of quarters ($0.25).
\n" ); document.write( "Jose has 6 more dimes than quarters. This can be written:
\n" ); document.write( "D = Q+6
\n" ); document.write( "The total amount of money is $1.65. This can be written:
\n" ); document.write( "($0.10)D+($0.25)Q = $1.65 Now substitute the first equation for D here.
\n" ); document.write( "($0.10)(Q+6)+($0.25)Q = $1.65 Simplify and solve for Q.
\n" ); document.write( "($0.10)Q + $0.60 + ($0.25)Q = $1.65 Combine like-terms.
\n" ); document.write( "($0.35)Q + $0.60 = $1.65 Subtract $0.60 from both sides.
\n" ); document.write( "($0.35)Q = $1.05 Divide both sides by ($0.35)
\n" ); document.write( "Q = 3 This is the number of quarters Jose has.
\n" ); document.write( "D = Q+6
\n" ); document.write( "D = 3+6 = 9 This is the number of dimes Jose has.
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