document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=872818>Question 872818</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, i have been haveing truble with this trig problem for a little while.\r<BR>\n" );
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document.write( "the question is,\r<BR>\n" );
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document.write( "Find the identical expression for the following, (tan^2 x + 2)/ (1+tan^2 x).\r<BR>\n" );
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document.write( "I have tried simplifying it to (tan^2 x + 2)/ sec ^2 x\r<BR>\n" );
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document.write( "then spliting the problem in two, (tan^2 x/ 1/ cos ^2 x) + (2/ 1/cos ^2 x)\r<BR>\n" );
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document.write( "this gave me, sin^2 x + 2cos^2 x.\r<BR>\n" );
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document.write( "This is where i get stuck, idk how to go any further to get the right answer please help me. =( </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526439 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (tan^2 x + 2)/(1+tan^2 x)\r<BR>\n" );
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document.write( "(tan^2 x + 1 + 1)/(tan^2 x + 1)\r<BR>\n" );
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document.write( "(tan^2 x + 1)/(tan^2 x + 1) + 1/(tan^2 x + 1)\r<BR>\n" );
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document.write( "1 + 1/(sec^2 x)\r<BR>\n" );
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document.write( "1 + cos^2 x  <font color=\"blue\"><--- You can stop here</font>\r<BR>\n" );
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document.write( "1 + (1 - sin^2 x)\r<BR>\n" );
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document.write( "1 + 1 - sin^2 x\r<BR>\n" );
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document.write( "2 - sin^2 x  <font color=\"blue\"><--- or you can stop here</font> </SPAN>\n" );
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