document.write( "Question 866679: |x|/(2x-1) >= 1\r
\n" ); document.write( "\n" ); document.write( "how do you solve this inequality?
\n" ); document.write( "im not sure how the working goes
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Algebra.Com's Answer #526435 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
|x|/(2x-1) >= 1
\n" ); document.write( "how do you solve this inequality
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\n" ); document.write( "|x|/(2x-1) ≥ 1
\n" ); document.write( "2-solutions:
\n" ); document.write( "case 1
\n" ); document.write( "x ≥ 2x-1
\n" ); document.write( "-x≥-1
\n" ); document.write( "x≤1
\n" ); document.write( "..
\n" ); document.write( "case 2
\n" ); document.write( "x≥-2x+1
\n" ); document.write( "-3x≥1
\n" ); document.write( "3x≤-1
\n" ); document.write( "x≤-1/3
\n" ); document.write( "..
\n" ); document.write( "Check:
\n" ); document.write( "for x≤1
\n" ); document.write( "|x|/(2x-1) =1/(2-1)=1
\n" ); document.write( "..
\n" ); document.write( "for x≤-1/3
\n" ); document.write( "|x|/(2x-1)=1/3/(-2/3+1)=(1/3)/(1/3)=1
\n" ); document.write( "check ok\r
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