document.write( "Question 73620: The following problem is not from a book.
\n" ); document.write( "Jose has 6 more dimes than quaters. If his coins total $ 1.65. How many coins of each type does he have. My solution is 3 quaters and 9 dimes. However I can not put it into an equation.\r
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Algebra.Com's Answer #52643 by bucky(2189)\"\" \"About 
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Let Q equal the unknown number of quarters he has and let D equal the unknown number of dimes.
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\n" ); document.write( "Since he has 6 more dimes than quarters we can say that if we added 6 to the number of
\n" ); document.write( "quarters that total would be the same as the number of dimes. In equation form this is:
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\n" ); document.write( "\"Q+%2B+6+=+D\"
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\n" ); document.write( "We also know that he has 165 cents total. If we multiply the number of quarters that he has
\n" ); document.write( "by 25 cents per quarter that will give us the total number of cents from quarters. In the
\n" ); document.write( "same way, if we multiply the number of dimes times 10 cents per dime that will give us
\n" ); document.write( "the number of cents from dimes. Added together the number of cents from quarters and
\n" ); document.write( "the number of cents from dimes must total 165. In equation form this is:
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\n" ); document.write( "\"%2825%2AQ%29%2B%2810%2AD%29+=+165\"
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\n" ); document.write( "From our first equation we know that D = Q + 6. Let's substitute Q + 6 for D in the second
\n" ); document.write( "equation that talks about cents. When we do that the second equation becomes:
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\n" ); document.write( "\"%2825%2AQ%29+%2B+10%2A%28Q+%2B+6%29+=+165\"
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\n" ); document.write( "Multiply on the left side to get:
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\n" ); document.write( "\"25%2AQ+%2B+10%2AQ+%2B+60+=+165\"
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\n" ); document.write( "Add the two terms containing Q:
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\n" ); document.write( "\"35%2AQ+%2B+60+=+165\"
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\n" ); document.write( "Eliminate the 60 on the left side by subtracting 60 from both sides of the equation to get:
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\n" ); document.write( "\"35%2AQ+=+105\"
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\n" ); document.write( "Finally divide both sides of this equation by 35 and you get:
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\n" ); document.write( "\"q+=+105%2F35+=+3\"
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\n" ); document.write( "So now we know that we have 3 quarters, just as you said. And since we know that we have
\n" ); document.write( "6 more dimes than quarters we know the number of dimes is \"6%2B3+=+9\".
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\n" ); document.write( "There's how you can get the answer of 3 quarters and 9 dimes.
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\n" ); document.write( "Hope this helps you to understand how to get the answer by mathematics.
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