document.write( "Question 872809: You are making a frame for a painting. The painting is 17in by 11in. You want the total area of the painting and frame to be 315in^2. The frame will be the same width on all sides. What should the outer dimensions of the frame be? \n" ); document.write( "
Algebra.Com's Answer #526418 by mananth(16946)\"\" \"About 
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Let the width be x
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\n" ); document.write( "Length of picture 17 in
\n" ); document.write( "width of picture 11 in
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\n" ); document.write( "Area = 187 In^2
\n" ); document.write( "Area of picture +frame 315 In^2
\n" ); document.write( "length of picture +frame 17 + 2 x
\n" ); document.write( "width of picture +frame 11 + 2 x
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\n" ); document.write( "( 17 + 2 x ) ( 11 + 2 x ) = 315
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\n" ); document.write( " 187 + 34 x + 22 x + 4 X^2 = 315
\n" ); document.write( " 4 X^2 + 56 x -128 = 0 \r
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\n" ); document.write( "\n" ); document.write( "4x^2+64x-8x-128=0\r
\n" ); document.write( "\n" ); document.write( "4x(x+16)-8(x+16)=0\r
\n" ); document.write( "\n" ); document.write( "(x+16)(4x-8)=0\r
\n" ); document.write( "\n" ); document.write( "x=-16 OR x=2\r
\n" ); document.write( "\n" ); document.write( "taking positive value\r
\n" ); document.write( "\n" ); document.write( "the outside dimensions are
\n" ); document.write( "19 by 13 in\r
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