document.write( "Question 872800: 1. Jason says that \"the sum of the squares of three consecutive integers is 112.\" Is this possible? If so, find the value of the integers. If not, explain mathematically. \r
\n" ); document.write( "\n" ); document.write( "I don't understand how I would set up the problem.
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Algebra.Com's Answer #526405 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
x^2 + (x+1)^2 + (x+2)^2 = 112
\n" ); document.write( "x^2 +x^2+2x+1 + x^2+4x+4 = 112
\n" ); document.write( " 3x^2 + 6x - 107 = 0
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"3x%5E2%2B6x%2B-107+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%286%29%5E2-4%2A3%2A-107=1320\".
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\n" ); document.write( " Discriminant d=1320 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-6%2B-sqrt%28+1320+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%286%29%2Bsqrt%28+1320+%29%29%2F2%5C3+=+5.05530070819498\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%286%29-sqrt%28+1320+%29%29%2F2%5C3+=+-7.05530070819498\"
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\n" ); document.write( " Quadratic expression \"3x%5E2%2B6x%2B-107\" can be factored:
\n" ); document.write( " \"3x%5E2%2B6x%2B-107+=+3%28x-5.05530070819498%29%2A%28x--7.05530070819498%29\"
\n" ); document.write( " Again, the answer is: 5.05530070819498, -7.05530070819498.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B6%2Ax%2B-107+%29\"
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