document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=872738>Question 872738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divided 56 into two parts such that three times the first part exceed one third of second  by 48. The parts are <BR>\n" );
document.write( "a. 25, 31 <BR>\n" );
document.write( "b.20,36 <BR>\n" );
document.write( "c.24, 32 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526342 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Divided 56 into two parts such that three times the first part exceed one third of second by 48. <BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Part one:: x<BR>\n" );
document.write( "Part two:: 56-x<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "3(56-x)-(1/3)x = 48<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( "168 - 3x - (1/3)x = 48<BR>\n" );
document.write( "-10/3 x = - 120<BR>\n" );
document.write( "(1/3)x = 12<BR>\n" );
document.write( "x = 36<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "56-x = 20<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-------------------\r<BR>\n" );
document.write( "\n" );
document.write( "The parts are <BR>\n" );
document.write( "a. 25, 31 <BR>\n" );
document.write( "b.20,36 <BR>\n" );
document.write( "c.24, 32<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );