document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=872723>Question 872723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liter of a 90% acid solution much be mixed with a 25% acid solution to get 650 L of 80% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526324 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many liter of a 90% acid solution much be mixed with a 25% acid solution to get 650 L of 80% acid solution?<BR>\n" );
document.write( "let X liters  90% acid solution added to Y liters of 25% acid solution<BR>\n" );
document.write( "as per conditions X+Y =650 (1)<BR>\n" );
document.write( "90% x+ 25%Y = 80%(X+Y)<BR>\n" );
document.write( "90x+25Y = 80x+80Y<BR>\n" );
document.write( "90X+25Y-80X-80Y =)<BR>\n" );
document.write( "10X-55Y =0<BR>\n" );
document.write( "10X=55Y<BR>\n" );
document.write( "X=55/10 y= 5.5 Y by substituting the value of x  in  equation (1)<BR>\n" );
document.write( "X+Y =650<BR>\n" );
document.write( "5.5y +Y =650<BR>\n" );
document.write( "6.5Y =650<BR>\n" );
document.write( "Y=650/6.5 =6500/65 =100 liters <BR>\n" );
document.write( "X+Y=650<BR>\n" );
document.write( "X+100 =650<BR>\n" );
document.write( "X=650-100 =550 liters <BR>\n" );
document.write( "Answer <BR>\n" );
document.write( "we should add 550 liters 90%acid solution to 100 liters of 25%acid solution <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );