document.write( "Question 872623: Given: W1•x = W2(L - x), where W1 and W2 are weights on either side
\n" ); document.write( " of a balance bar, x is the distance from W1 to the
\n" ); document.write( " folcrum point, and \"L\" is the length of the balance bar.
\n" ); document.write( " What weight must be applied to the right end of an 8 foot long
\n" ); document.write( " balance bar (of negligible weight) to balance a 70 pound child on
\n" ); document.write( " the left end who is located 1 foot away from the fulcrum point?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #526319 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
That's a very strange see-saw, and will not be much fun for that child, but I guess the numbers were chosen to make the arithmetic easier, and I like that.
\n" ); document.write( " \"70%2A1=W2%2A7\"-->\"70=7W2\"-->\"70%2F7=W2\"-->\"highlight%28W2=10%29\"
\n" ); document.write( "So there you have it. A 10 pound weight at the end of the long arm of that see-saw, will allow that 70 pound child to bounce up and down by about 1 foot. Weee!
\n" ); document.write( " --->
\n" ); document.write( "
\n" );