document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=872713>Question 872713</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factoring trinomials:\r<BR>\n" );
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document.write( "-60z^5 + 65z^4 + 20z^3\r<BR>\n" );
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document.write( "I have worked this far...\r<BR>\n" );
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document.write( "-5z^3(12z^2-13z-4)\r<BR>\n" );
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document.write( "12*4= 48 with a sum of -13\r<BR>\n" );
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document.write( "Just not quite sure how to always pick the two integers to get the product of 48 and the sum of -13. This is not the only question. Is there a faster simpler way to find the two numbers? Thank you for your help.\r<BR>\n" );
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document.write( "James </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526318 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -60z^5 + 65z^4 + 20z^3 <BR>\n" );
document.write( "-5z^3(12z^2 -13z -4)<BR>\n" );
document.write( "now factor the expression within parenthesis, start by finding the prime factors of 4 and 12<BR>\n" );
document.write( "4 = 2^2 * 1 and 12 = 3*2^2<BR>\n" );
document.write( "for 12, I will try 3 and 4 and for 4, I will try 4 and 1<BR>\n" );
document.write( "(3z - 4)(4z + 1) = 12z^2 -13z -4<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "-60z^5 + 65z^4 + 20z^3 = -5z^3(3z - 4)(4z + 1)<BR>\n" );
document.write( " </SPAN>\n" );
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