document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=872689>Question 872689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a certain manufacturing process, the probability of a type I defect is 0.09, the probability of a type II defect is 0.05, and the probability of having both types of defects is 0.02. Find the probability that neither defect occurs. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526309 by </B><A HREF=/tutors/aboutme.mpl?userid=indra89811><B>indra89811(24)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=indra89811><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=indra89811><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let P(A) =Type 1 is defective=0.09<BR>\n" );
document.write( "P(B)=Type 2 is defective=0.05<BR>\n" );
document.write( "P(A and B)=Both are defective=0.02<BR>\n" );
document.write( "P(A or B)=P(A)+P(B)-P(A and B)<BR>\n" );
document.write( "P(Type 1 is defective or type 2 is defective) indicates <BR>\n" );
document.write( "P(A or B)=0.09+0.05-0.02=0.12\r<BR>\n" );
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document.write( "Probability that none are defective=1-0.12=0.88\r<BR>\n" );
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document.write( "Ans=0.88\r<BR>\n" );
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document.write( "------------------Peace out hun--------------- :)<BR>\n" );
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