document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=872621>Question 872621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given: t = f•L, where \"t\" is torque, \"f\" is force, and \"L\" is length.<BR>\n" );
document.write( " What force (in pounds) must be applied to an 0.8 ft long torque<BR>\n" );
document.write( " rench to achieve the same torque generated by a 100 lb force<BR>\n" );
document.write( " applied to an 0.5 ft long torque wrench?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526301 by </B><A HREF=/tutors/aboutme.mpl?userid=indra89811><B>indra89811(24)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=indra89811><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=indra89811><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The torque generate by a 100 lb force on 0.5 ft long wrench = 100 * 0.5 = 50\r<BR>\n" );
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document.write( "Force applied to an 0.8 ft long torque wrench to achieve a torque of 50 can be expressed as<BR>\n" );
document.write( "0.8*f=50<BR>\n" );
document.write( "f=50/0.8=62.5 lb\r<BR>\n" );
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document.write( "Therefore, the required force to be applied is 62.5 lb. </SPAN>\n" );
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