document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=872641>Question 872641</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train B speeding with 1290 km/ h crosses another train C running in the same direction, in 2 minutes,if the length of the train B And C be 100 m and 200 m respectively,what is the speed (in km/h) of the train C? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526278 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526278\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Never heard of a train speed of 1290 km/h. Love to go. If your problem says 1290 then add a zero and recalculate\r<BR>\n" );
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document.write( "speed difference =129-x\r<BR>\n" );
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document.write( "distance to cross 300m = 0.3 km\r<BR>\n" );
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document.write( "d/r = t\r<BR>\n" );
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document.write( ".3/129-x= 2/60\r<BR>\n" );
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document.write( "60*.3=2(129-x)\r<BR>\n" );
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document.write( "18 =258-2x\r<BR>\n" );
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document.write( "2x= 240\r<BR>\n" );
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document.write( "x=120 km/h\r<BR>\n" );
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document.write( " </SPAN>\n" );
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