document.write( "Question 872557: Solve
\n" ); document.write( "a) log(base 2)(x-5) + log(base 2) (x-2) = 2
\n" ); document.write( "Can you please help me out? Thanks so much in advance:)\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #526257 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
log(base 2)(x-5) + log(base 2) (x-2) = 2
\n" ); document.write( ".
\n" ); document.write( "log(2,x-5) + log(2,x-2) = 2
\n" ); document.write( "log(2,(x-5)(x-2)) = 2
\n" ); document.write( "(x-5)(x-2) = 2^2
\n" ); document.write( "(x-5)(x-2) = 4
\n" ); document.write( "x^2-7x+10 = 4
\n" ); document.write( "x^2-7x+6 = 0
\n" ); document.write( "(x-6)(x-1) = 0
\n" ); document.write( ".
\n" ); document.write( "x = {1, 6}
\n" ); document.write( "You have to throw out 1 (extraneous) leaving
\n" ); document.write( "x = 6
\n" ); document.write( "
\n" ); document.write( "
\n" );