document.write( "Question 872600: Question text
\n" ); document.write( "Calculate the minimum sample size for a study of the cost of 1 full year (tuition as well as room and board) when the level of confidence is 99%, the standard deviation is $1000 and the allowable error is $1600.
\n" ); document.write( "
\n" ); document.write( "Enter your response as a whole number.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #526245 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
ME = z*s/sqrt(n)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "ME*sqrt(n) = z*s\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "sqrt(n) = z*s/ME\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "n = (z*s/ME)^2\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "n = (2.576*1000/1600)^2 ... z = 2.576 is found using a table (critical value for 99% confidence interval)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "n = 2.5921\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "n = 3 ... round UP to the nearest whole number\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The min sample size is 3
\n" ); document.write( "
\n" ); document.write( "
\n" );