document.write( "Question 872589: If an object is thrown upward with an initial velocity of 15ft per second, its hight is given by h=-15t^2+90t after t seconds. What it its maximum height? \n" ); document.write( "
Algebra.Com's Answer #526244 by mananth(16949) You can put this solution on YOUR website! h=-15t^2+90t\r \n" ); document.write( "\n" ); document.write( "the vertex of a parabola is at \r \n" ); document.write( "\n" ); document.write( "x= -b/2a\r \n" ); document.write( "\n" ); document.write( "b=90\r \n" ); document.write( "\n" ); document.write( "a=-15\r \n" ); document.write( "\n" ); document.write( "x= -90/-30 \n" ); document.write( "x= 3 \r \n" ); document.write( "\n" ); document.write( "plug x = 3 to get the y co ordinate or h\r \n" ); document.write( "\n" ); document.write( "h= -15*(3)^2+90*(3)\r \n" ); document.write( "\n" ); document.write( "h=135 feet the maximum height\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |