document.write( "Question 872469: 11. The monthly incomes for 12 randomly selected people, each with a bachelor’s degree in economics, are shown below.
\n" ); document.write( "Assume the population is normally distributed.
\n" ); document.write( "4450.36 4596.43 4366.26
\n" ); document.write( "4455.52 4151.31 4407.46
\n" ); document.write( "4283.11 4527.74 4407.46
\n" ); document.write( "3946.48 4023.48 4221.98
\n" ); document.write( "a. Find the sample mean.
\n" ); document.write( "b. Find the sample standard deviation.
\n" ); document.write( "c. Construct a 99% confidence interval for the population mean μ.
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Algebra.Com's Answer #526179 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "a) mean = 4319.80
\n" ); document.write( "b) SD = 199.83 (Using (n-1)
\n" ); document.write( "ME(99% Confidence Interval, df = 11) = 3.106*199.83/sqrt(12)
\n" ); document.write( "CI: CI: 4319.80 -ME < u < 4319.80 + ME \n" ); document.write( "
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