document.write( "Question 872440: the sum of the squares of two numbers is 233 and one of the number is 3 less than twice the other number. find the number. give the solution of this equation in quadratic equation \n" ); document.write( "
Algebra.Com's Answer #526172 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi
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document.write( "x^2 + (2x-3)^2 = 233
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document.write( "x^2 + 4x^2 - 12x + 9 = 233
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document.write( "5x^2 -12x -224 = 0   |format: a^2 + bx + c = 0
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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document.write( " \"x+=+%2812+%2B-+sqrt%28+4624+%29%29%2F%2810%29+\" 
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document.write( " \"x+=+%2812+%2B-+68%29%2F%2810%29+\" 
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document.write( "  x = -5.6, 8 \n" );
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