document.write( "Question 73491This question is from textbook Intermediate Algebra
\n" ); document.write( ": I have already worked this problem, but think I got confused and mixed up a couple of steps. Could you please provide me with the proper steps so I can evaluate my original work and see what I did wrong.\r
\n" ); document.write( "\n" ); document.write( "Simplify and evaluate:
\n" ); document.write( "(2x^-6y^-4z^0/3^-2x^-2y^-8z^5)^3
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Algebra.Com's Answer #52609 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%282x%5E-6y%5E-4z%5E0%2F3%5E-2x%5E-2y%5E-8z%5E5%29%5E3\"Start with the original problem
\n" ); document.write( "Since \"%28x%5Ey%29%5Ez=x%5E%28y%2Az%29\" the problem can be rewritten as this. Remember each term is raised to the 3rd power, so this rule applies to each term.
\n" ); document.write( "Simplify the exponents
\n" ); document.write( "Remember to divide variables with exponents, you just subtract the exponents. (eg \"x%5E2%2Fx%5E1=x%5E%282-1%29=x%5E1\" Also \"x%5E0=1\"
\n" ); document.write( "\"%288x%5E%28-12%29%29y%5E%2812%29z%5E%28-15%29%2F3%5E%28-6%29%29\"
\n" ); document.write( "Finally anything raised to a negative power is inverted (ie \"x%5E%28-2%29=1%2Fx%5E2\")
\n" ); document.write( "\"%283%5E6%29%288%29y%5E%2812%29%2Fx%5E%2812%29z%5E%2815%29%29\"
\n" ); document.write( "\"%28729%29%288%29y%5E%2812%29%2Fx%5E%2812%29z%5E%2815%29%29\"
\n" ); document.write( "\"%285832%29y%5E%2812%29%2Fx%5E%2812%29z%5E%2815%29%29\"Here it is in simplified form
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