document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=872322>Question 872322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A machine shop needs to make a small automotive part by drilling four holes of radius r from flat circular piece of radiusR. The area of the resulting part is eight square inches. Write an equation that relates r and R. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526050 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The big circle has an area of pi*R^2\r<BR>\n" );
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document.write( "The small circles have individual areas of pi*r^2 and there are 4 of them, so they total to 4*pi*r^2\r<BR>\n" );
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document.write( "(Area of Big circle) - (Area of little circles) = Resulting area\r<BR>\n" );
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document.write( "pi*R^2 - 4*pi*r^2 = 8\r<BR>\n" );
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document.write( "you can optionally factor out pi to get\r<BR>\n" );
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document.write( "pi*(R^2 - 4r^2) = 8\r<BR>\n" );
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document.write( "and then factor the remaining bit using the difference of squares rule to get\r<BR>\n" );
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document.write( "pi*(R - 2r)*(R + 2r) = 8 </SPAN>\n" );
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