document.write( "Question 73485: One solution is 10% acid and another is 25%acid. Howmany litres ofeach should be mixed to form 30L of a solution that is 18% acid? \n" ); document.write( "
Algebra.Com's Answer #52604 by Earlsdon(6294)\"\" \"About 
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Let x = the required number of liters of 10% acid solution, then (30-x) = the required number of liters of 25% acid solution. The sum of these will make up the 30 liters of 18% acid solution. After changing the percentages to their decimal equivalents, we can write the necessary equation to solve for x.\r
\n" ); document.write( "\n" ); document.write( "\"0.1x+%2B+0.25%2830-x%29+=+0.18%2830%29\" Simplify and solve for x.
\n" ); document.write( "\"0.1x+%2B+7.5+-+0.25x+=+5.4\" Combine like-terms.
\n" ); document.write( "\"-0.15x+%2B+7.5+=+5.4\" Subtract 7.5 from both sides.
\n" ); document.write( "\"-0.15x+=+-2.1\" Divide both sides by -0.15
\n" ); document.write( "\"x+=+14\" and \"30-x+=+30-14\" = \"16\"
\n" ); document.write( "Solution:
\n" ); document.write( "You will need 14 liters of 10% acid solution plus 16 liters of 25% acid solution to make 30 liters of 18% acid solutution.\r
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