document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=872264>Question 872264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I do I find sec 0, in terms of cot 0? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526037 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find sec 0, in terms of cot 0?<BR>\n" );
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document.write( "Since sin^2 + cos^2 = 1,<BR>\n" );
document.write( "dividing by cos^2 you get:<BR>\n" );
document.write( "tan^2 + 1 = sec^2<BR>\n" );
document.write( "----<BR>\n" );
document.write( "So, sec = sqrt[tan^2+1]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Then, sec = sqrt[(1/cot)^2 + 1]<BR>\n" );
document.write( "----<BR>\n" );
document.write( "sec = sqrt[(1+cot^2)/cot^2]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "sec = sqrt(1+cot^2)/cot<BR>\n" );
document.write( "-----------------------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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