document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=872292>Question 872292</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The points (5,k) and (k, 3) lie on a line perpendicular to a line with a slope of 3/4. What is the value of k?<BR>\n" );
document.write( "So far I have arrived at <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+3%2F4+=+%283-k%29%2F%28k-5%29 ALIGN=MIDDLE  ALT=\"+3%2F4+=+%283-k%29%2F%28k-5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > using <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+m=%28Y2-Y1%29%2F%28X2-X1%29 ALIGN=MIDDLE  ALT=\"+m=%28Y2-Y1%29%2F%28X2-X1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > but i do not know how to proceed from there. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526036 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the points are on the line perpendicular to a line with slope 3/4\r<BR>\n" );
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document.write( "so the slope of the line joining these points will be -4/3\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+-4%2F3+=+%283-k%29%2F%28k-5%29 ALIGN=MIDDLE  ALT=\"+-4%2F3+=+%283-k%29%2F%28k-5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "cross multiply\r<BR>\n" );
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document.write( "-4(k-5)=3(3-k)\r<BR>\n" );
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document.write( "-4k+20=9-3k\r<BR>\n" );
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document.write( "k=11 </SPAN>\n" );
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