document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73464>Question 73464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line satisfying the given conditions : Perpendicular to the graph of y + 6 = -1/3x and passes through the point at (-4,-5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52600 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y+6=-X/3<BR>\n" );
document.write( "Y=-X/3-6 THIS LINE HAS A SLOPE OF -1/3 SO A PERPENDICULAR LINE HAS A SLOPE OF 3.<BR>\n" );
document.write( "NOW REEPLACE THE X&Y VALUES & THE SLOPE (m) IN THE LINE EQUATION (Y=mX+b) & SOLVE FOR THE Y INTERCEPT(b)<BR>\n" );
document.write( "-5=-4*3+b<BR>\n" );
document.write( "-5=-12+b<BR>\n" );
document.write( "b=-5+12<BR>\n" );
document.write( "b=7 THUS THE LINE EQUATION IS:<BR>\n" );
document.write( "Y=3X+7<BR>\n" );
document.write( "FOLLOWING IS THE GRAPH OF THESE TWO LINES:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+y+=+-x%2F3+-6%2C+y+=+3x+%2B7%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+y+=+-x%2F3+-6%2C+y+=+3x+%2B7%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = -x/3 -6 and y = 3x +7).  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );