document.write( "Question 871914: )
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\n" ); document.write( "The table below shows the numbers of two- to five-bedroom houses in the Belmont neighborhood.\r
\n" ); document.write( "\n" ); document.write( "Number of Bedrooms Frequency
\n" ); document.write( "2 12
\n" ); document.write( "3 40
\n" ); document.write( "4 70
\n" ); document.write( "5 3\r
\n" ); document.write( "\n" ); document.write( "What is the probability that a randomly selected house will have 3 or fewer bedrooms?
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\n" ); document.write( "A)
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\n" ); document.write( "0.560
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\n" ); document.write( "B)
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\n" ); document.write( "0.416
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\n" ); document.write( "C)
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\n" ); document.write( "0.320
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\n" ); document.write( "D)
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\n" ); document.write( "0.584
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Algebra.Com's Answer #525951 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

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Number of BedroomsFrequency
212
340
470
53
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\n" ); document.write( "\n" ); document.write( "There are 12+40+70+3 = 125 homes being surveyed.\r
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\n" ); document.write( "\n" ); document.write( "\"3 or fewer\" means \"at most 3\" (think of it as the ceiling or as high as you can go). X = 2 is the lowest you can go on the table while X = 3 is the highest we want. So we just need to calculate P(X = 2) and P(X = 3) then add up them. The variable X is defined as X = number of bedrooms.\r
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\n" ); document.write( "\n" ); document.write( "From the table, we get the following probabilities\r
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\n" ); document.write( "\n" ); document.write( "P(X = 2) = 12/125
\n" ); document.write( "P(X = 3) = 40/125\r
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\n" ); document.write( "\n" ); document.write( "Use them to calculate P(X <= 3)\r
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\n" ); document.write( "\n" ); document.write( "P(X <= 3) = P(X = 2) + P(X = 3)
\n" ); document.write( "P(X <= 3) = 12/125 + 40/125
\n" ); document.write( "P(X <= 3) = (12 + 40)/125
\n" ); document.write( "P(X <= 3) = 52/125
\n" ); document.write( "P(X <= 3) = 0.416\r
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\n" ); document.write( "\n" ); document.write( "So the final answer is 0.416
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