document.write( "Question 867943: I'm having trouble with this problem. I get parts of it but can't seem to understand what the total variable is. Here is the problem:
\n" ); document.write( "A town has an ice cream shop, a bowling alley, and a park. Students hang out at one of these 3 places on a Friday night. A given student re-evaluates the choice to be at a particular location every 10 minutes as follow:
\n" ); document.write( "1. If at the park, the student goes to the bowling alley 10% of the time, the ice cream shop 20% of the time, and the otherwise stays put.
\n" ); document.write( "2. If at the bowling alley, the student goes to the park 5% of the time, to the ice cream shop 10% of the time, and otherwise stays put.
\n" ); document.write( "3. If at the ice cream shop, the student goes to the park 35% of the time, to the bowling alley 15% of the time, and otherwise stays put. \r
\n" ); document.write( "\n" ); document.write( "The police drive by the park and tell the students there to go home. Estimate the fraction of students that was told to go home, (from the park). \r
\n" ); document.write( "\n" ); document.write( "I get what percentage of the time for each occasion the student goes to the park, but how can I make this into a formula so that I can solve it when each occasion is conditional and there is no clear total variable given. Any help with this will be greatly appreciated. Thank you very much.
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Algebra.Com's Answer #525934 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
Let's start with 100 in each place
\n" ); document.write( "b(1)=100 i(1)=100 p(1)=100
\n" ); document.write( "1)b(2)=b(1)+.10*p(1)
\n" ); document.write( "1)i(2)=i(1)+.20*p(1)
\n" ); document.write( "1)p(2)=.70*p(1)
\n" ); document.write( "2)p(2)=p(2)+.05*b(1)
\n" ); document.write( "2)i(2)=i(2)+.10*b(1)
\n" ); document.write( "2)b(2)=.85*b(1)
\n" ); document.write( "3)p(2)=p(2)+.35*i(1)
\n" ); document.write( "3)b(2)=b(2)+.15*i(1)
\n" ); document.write( "3)i(2)=.50*i(1)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "0)b(1)=100
\n" ); document.write( "2)b(2)=.85*b(1)
\n" ); document.write( "1)b(2)=b(1)+.10*p(1)
\n" ); document.write( "3)b(2)=b(2)+.15*i(1)
\n" ); document.write( "85+15+10=110
\n" ); document.write( "i's
\n" ); document.write( "0)i(1)=100
\n" ); document.write( "3)i(2)=.50*i(1)
\n" ); document.write( "1)i(2)=i(1)+.20*p(1)
\n" ); document.write( "2)i(2)=i(2)+.10*b(1)\r
\n" ); document.write( "\n" ); document.write( "50+20+10=80
\n" ); document.write( "p's
\n" ); document.write( "0)p(1)=100
\n" ); document.write( "1)p(2)=.70*p(1)
\n" ); document.write( "2)p(2)=p(2)+.05*b(1)
\n" ); document.write( "3)p(2)=p(2)+.35*i(1)
\n" ); document.write( "70+5+35=110
\n" ); document.write( "We are only interested in p
\n" ); document.write( "110 in the park after 10 minutes
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