document.write( "Question 872074: A survey indicates 40% of households in the USA own CD players from a random sample of 250 households in the USA find the probability that the number of households who own CD players is:\r
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document.write( "a) exactly 95\r
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document.write( "b) between 105 and 110\r
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document.write( "c) at most 85\r
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document.write( "d) at least 95 \n" );
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Algebra.Com's Answer #525886 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! p = .40, n = 250 \n" ); document.write( "P(x = 95) = binompdf(250, .40, 95) = .0421 0r 4.21% \n" ); document.write( "P(105 ≤ x ≤ 110) = binomcdf(250, .40, 110)- binomcdf(250, .40, 104) = .9119 - .7203 = .1916 0r 19.16% \n" ); document.write( "P(x ≤ ≤ 85) = binomcdf(250, .40, 85) = .0297 0r 2.97% \n" ); document.write( "P(x ≥ 95) = 1 - (1-binomcdf(250, .40, 94) = .7605 0r 76.05% \n" ); document.write( " |