document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=871993>Question 871993</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of the rectangle shown is 63 in^2. Find the length and width of the rectangle.\r<BR>\n" );
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document.write( "Below this there is a rectangle with the length as (x+8) and the width as (2x+5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #525841 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=525841\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area(A) = length times width<BR>\n" );
document.write( "A = (x+8) times (2x+5)<BR>\n" );
document.write( "63 = 2x^2 + 21x + 40<BR>\n" );
document.write( "2x^2 + 21x - 23 = 0<BR>\n" );
document.write( "this factors into<BR>\n" );
document.write( "(2x+23) times (x-1) = 0<BR>\n" );
document.write( "x = -23/2 or 1<BR>\n" );
document.write( "x = 1 is the correct answer<BR>\n" );
document.write( "length = x + 8 = 9 inches<BR>\n" );
document.write( "width = 2x + 5 = 7 inches<BR>\n" );
document.write( "note that Area = 9 times 7 = 63 cm^2<BR>\n" );
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