document.write( "Question 871878: A fashion magazine claims that females like to “shop” more than males. In interviews with 1000
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document.write( "randomly selected females, the magazine found that 700 like to “shop”. Also, it was found that 520 out of 800
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document.write( "randomly selected males like to “shop”. Test the magazines claim by a 0.02 level of significance. State the
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document.write( "practical conclusion that refers to the information in this question. \n" );
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Algebra.Com's Answer #525777 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A fashion magazine claims that females like to “shop” more than males. In interviews with 1000 randomly selected females, the magazine found that 700 like to “shop”. \n" ); document.write( "-------------------- \n" ); document.write( "Also, it was found that 520 out of 800 randomly selected males like to “shop”. \n" ); document.write( "-------------------- \n" ); document.write( "Test the magazines claim by a 0.02 level of significance. \n" ); document.write( "----- \n" ); document.write( "Ho: p(f)-p(m) <= 0 \n" ); document.write( "Ha: p(f)-p(m) > 0 (claim) \n" ); document.write( "------ \n" ); document.write( "t[(700/1000)-(520/800)] = (0.7-0.65)/sqrt[[(0.7*0.3/1000) + (0.65*0.35/800)] \n" ); document.write( "= 2.2488 \n" ); document.write( "------- \n" ); document.write( "P-value = P(t > 2.2488 when df = 1800-2)) = tcdf(2.2488,100,1798) = 0.0159 \n" ); document.write( "-------------- \n" ); document.write( "Since the p-value is less than 2%, reject Ho. \n" ); document.write( "The test results support the claim. \n" ); document.write( "-------------------- \n" ); document.write( "State the practical conclusion that refers to the information in this question. \n" ); document.write( "Women like to shop more than men. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " \n" ); document.write( " |