document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=871844>Question 871844</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorboat travels 40 miles downstream (traveling with the current) in 2 and 1/2 hours. The river's current is known to be 2mph. \r<BR>\n" );
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document.write( "A.) What was the speed of the motor boat in still water?\r<BR>\n" );
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document.write( "B.) If the boat maintains the same still-water speed, how long will it take the boat to return, given that it will be traveling upstream (traveling against the current) ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #525750 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=525750\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 40 miles in 2 hours so \r<BR>\n" );
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document.write( "speed with current = 40/2.5 = 16 mph\r<BR>\n" );
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document.write( "speed of current = 2 mph\r<BR>\n" );
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document.write( "so speed of boat in still water = 16-2 = 14 mph\r<BR>\n" );
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document.write( "when travelling upstream the speed will be 14-2 = 12 mph\r<BR>\n" );
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document.write( "t= 40/12 = 3.33 hours\r<BR>\n" );
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document.write( " </SPAN>\n" );
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