document.write( "Question 73450: a chord of a circle is 4 inches from the center. If the diameter of the circle is 10 inches, find the length of the chord. \n" ); document.write( "
Algebra.Com's Answer #52572 by Edwin McCravy(20056)\"\" \"About 
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document.write( "a chord of a circle is 4 inches from the center. \r\n" );
document.write( "If the diameter of the circle is 10 inches, find \r\n" );
document.write( "the length of the chord.\r\n" );
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document.write( "I can't draw on here, so follow my instructions\r\n" );
document.write( "and draw it on your paper.\r\n" );
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document.write( "Since the diameter is 10 inches, the radius is \r\n" );
document.write( "5 in. Draw a circle with radius 5 inches.  Label \r\n" );
document.write( "the center O. \r\n" );
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document.write( "Draw a radius OA.  Locate point B on OA 4 inches \r\n" );
document.write( "from O (and 1 inch from A).\r\n" );
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document.write( "Draw chord CD through B perpendicular to OA.\r\n" );
document.write( "Draw radii OC and OD.\r\n" );
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document.write( "Triangles OBC and OBD are congruent right triangles.\r\n" );
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document.write( "Use the Pythagorean theorem on right triangle OBC:\r\n" );
document.write( "OC has measure 5 inches because it is a radius.\r\n" );
document.write( "OB has meanure 4 inches because that is given. So\r\n" );
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document.write( "OC² = OB² + BC²\r\n" );
document.write( " 5² = 4² + BC²\r\n" );
document.write( " 25 = 16 + BC²\r\n" );
document.write( "  9 = BC²\r\n" );
document.write( " Ö9 = BC\r\n" );
document.write( "  3 = BC\r\n" );
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document.write( "So BC has measure 3 inches.  By congruent right \r\n" );
document.write( "triangles, BD also has measure 3 inches.  So\r\n" );
document.write( "chord CD = BC + BD = 3 in + 3 in = 6 in.\r\n" );
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document.write( "Edwin
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