document.write( "Question 871651: Sixty-two percent of adults in the US have an HDTV in their home. You randomly select 45 adults in the US and ask them if they have an HDTV in their home. What is the probability that fewer than 20 of them respond yes? \n" ); document.write( "
Algebra.Com's Answer #525670 by ewatrrr(24785)\"\" \"About 
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p = .62, n = 45
\n" ); document.write( "P(x < 20) = 1 - binomcdf(45, .62, 20) = 1 - .9944 = .0056 0r .56%
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