document.write( "Question 871515: Five years later a boy's age will be 4 times the square of what it was 9 years ago. Find his present age. \n" ); document.write( "
Algebra.Com's Answer #525571 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "x = the boy's age now\r\n" ); document.write( "x+5 = the boy's age five years later\r\n" ); document.write( "x-9 = what the boy's age was 9 years ago\r\n" ); document.write( "(x-9)² = the square of what it was 9 years ago \r\n" ); document.write( "4(x-9)² = 4 times the square of what it was 9 years ago\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " x+5 = 4(x-9)²\r\n" ); document.write( " x+5 = 4(x-9)(x-9)\r\n" ); document.write( " x+5 = 4(x²-9x-9x+81)\r\n" ); document.write( " x+5 = 4(x²-18x+81)\r\n" ); document.write( " x+5 = 4x²-72x+324\r\n" ); document.write( " 0 = 4x²-73x+319\r\n" ); document.write( " 0 = (4x-29)(x-11)\r\n" ); document.write( "\r\n" ); document.write( " 4x-29 = 0; x-11 = 0\r\n" ); document.write( " 4x = 29 x = 11 \r\n" ); document.write( " x =\n" ); document.write( " |