document.write( "Question 73390: Solve for x;\r
\n" );
document.write( "\n" );
document.write( "7(3x+11) = 9(3-6x) \n" );
document.write( "
Algebra.Com's Answer #52555 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( ". \n" ); document.write( "7(3x+11) = 9(3-6x) \n" ); document.write( ". \n" ); document.write( "Solve for x \n" ); document.write( ". \n" ); document.write( "First, on the left side multiply the 7 by each of the terms in the parentheses to get: \n" ); document.write( ". \n" ); document.write( "21x + 77 = 9(3 - 6x) \n" ); document.write( ". \n" ); document.write( "Now on the right side multiply 9 times each of the terms in the parentheses to get: \n" ); document.write( ". \n" ); document.write( "21x + 77 = 27 - 54x \n" ); document.write( ". \n" ); document.write( "Now the object is to get all the terms with x on the right side and all the terms that \n" ); document.write( "are just numbers onto the right side. \n" ); document.write( ". \n" ); document.write( "Begin by adding 54x to both sides of the equation. On the right side this cancels \n" ); document.write( "the - 54x. The equation then becomes: \n" ); document.write( ". \n" ); document.write( "75x + 77 = 27 \n" ); document.write( ". \n" ); document.write( "Now subtract 77 from both sides to get rid of the + 77 on the left side. When you do \n" ); document.write( "this subtraction the equation becomes \n" ); document.write( ". \n" ); document.write( "75x = -50 \n" ); document.write( ". \n" ); document.write( "Finally solve for x by dividing both sides by the multiplier of x which is 75. \n" ); document.write( ". \n" ); document.write( "x = -50/75 = -2/3 \n" ); document.write( ". \n" ); document.write( "So the answer to this problem is x = -2/3 \n" ); document.write( ". \n" ); document.write( "Hope that this gives you a little insight into the procedures that can be used to solve \n" ); document.write( "equations. \n" ); document.write( " |