document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=871344>Question 871344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi can someone please help me out on this? \r<BR>\n" );
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document.write( "The diameter of a clock’s face is 6 inches. Find the length of the minor arc formed by the hands of the clock at 4:00. Round to the nearest hundredth.\r<BR>\n" );
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document.write( "Thanks a lot!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #525494 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=525494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diameter of a clock’s face is 6 inches.<BR>\n" );
document.write( " Find the length of the minor arc formed by the hands of the clock at 4:00.<BR>\n" );
document.write( " Round to the nearest hundredth.<BR>\n" );
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document.write( "Find what portion of 360 degrees is 4 o'clock: 4/12 = 1/3<BR>\n" );
document.write( "Find the circumference of the clock<BR>\n" );
document.write( "C = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A6 ALIGN=MIDDLE  ALT=\"pi%2A6\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 18.85 inchec<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > * 18.85 = 6.28 inches is the arc formed between the hands at 4 o'clock </SPAN>\n" );
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