document.write( "Question 871289: Please help me with this question!
\n" ); document.write( "Find the vertex, focus, directrix, and focal width of the parabola.
\n" ); document.write( " $\"+%28-1%2F16%29+x%5E2+=+y+\"$ \n" ); document.write( "

Algebra.Com's Answer #525429 by lwsshak3(11628) $\"\"$ $\"About$

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Find the vertex, focus, directrix, and focal width of the parabola.
\n" ); document.write( " $\"+%28-1%2F16%29+x%5E2+=+y+\"$
\n" ); document.write( "x^2=-16y
\n" ); document.write( "This is an equation of a parabola that opens downward with vertex at the origin.
\n" ); document.write( "Its basic equation: x^2=-4py
\n" ); document.write( "For given parabola:
\n" ); document.write( "vertex: (0,0)
\n" ); document.write( "axis of symmetry: x=0
\n" ); document.write( "4p=16
\n" ); document.write( "p=4
\n" ); document.write( "focus: (0,-4)(p-distance below vertex on the axis of symmetry)
\n" ); document.write( "directrix:y=4 (p-distance above vertex on the axis of symmetry)
\n" ); document.write( "focal width=4p=16
\n" ); document.write( " \n" ); document.write( "

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