document.write( "Question 871249: 3+6e^-2x=7\r
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Algebra.Com's Answer #525398 by Fombitz(32388)\"\" \"About 
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\"3%2B6e%5E%28-2x%29=7\"
\n" ); document.write( "\"6e%5E%28-2x%29=4\"
\n" ); document.write( "\"e%5E%28-2x%29=4%2F6=2%2F3\"
\n" ); document.write( "\"-2x=ln%282%2F3%29\"
\n" ); document.write( "\"x=-%281%2F2%29ln%282%2F3%29\"
\n" ); document.write( "\"x=%281%2F2%29ln%283%2F2%29\"
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