document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=871176>Question 871176</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sector of a circle of radius 18 mi has an area of 162 mi^2. Find the central angle of the sector. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #525395 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=525395\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A sector of a circle of radius 18 mi has an area of 162 mi^2. Find the central angle of the sector.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Let the angle-measure of the sector be \"x\"::<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "Area of sector = (x/360)(pi*18^2) = 162 sq mi<BR>\n" );
document.write( "----<BR>\n" );
document.write( "(x/360) = 0.1592<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = 57.30 degrees<BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "===============   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );