document.write( "Question 73405This question is from textbook
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document.write( ": A clerk is assigned a job that she can complete in 8 hours. After she has been working for 2 hours, another clerk, who is able to do this job in 10 hours, is assigned to help her. In how many hours will the clerks working together complete the job. \n" );
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Algebra.Com's Answer #52535 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A clerk is assigned a job that she can complete in 8 hours. After she has been working for 2 hours, another clerk, who is able to do this job in 10 hours, is assigned to help her. In how many hours will the clerks working together complete the job. \n" ); document.write( ": \n" ); document.write( "Let t = number of hrs required to complete the job when working together. \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "The 1st clerk completed 2/8 = 1/4 of the job when the 2nd clerk joined in. \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by 40 to get rid of the denominators, resulting in: \n" ); document.write( "10 + 5t + 4t = 40 \n" ); document.write( ": \n" ); document.write( "9t = 40 - 10 \n" ); document.write( "9t = 30 \n" ); document.write( "t = 30/9 \n" ); document.write( "t = 10/3 hrs to complete the job, that would be 2 hrs 20 min \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution t=10/3 using 10 + 5t + 4t = 40 \n" ); document.write( "10 + 5(10/3) + 4(10/3) = \n" ); document.write( "10 + 50/3 + 40/3 = \n" ); document.write( "30/3 + 50/3 + 40/3 = 120/3 = 40 \n" ); document.write( ": \n" ); document.write( "How about this? Did it make sense to you? \n" ); document.write( " |