document.write( "Question 871093: Find the exact value of the expression.\r
\n" ); document.write( "\n" ); document.write( "sin(cos^-1 2/3 - tan^-1 1/4)
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Algebra.Com's Answer #525332 by KMST(5328)\"\" \"About 
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NOTE: I am rushing to get done before I have to go to my day job, so check for mistakes.
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\n" ); document.write( "In this problem \"cos^-1\" means the inverse function of cosine,
\n" ); document.write( "and \"tan^-1\" means the inverse function of tangent.
\n" ); document.write( "We are looking for the exact value of
\n" ); document.write( "\"sin%28A-B%29\" knowing that \"cos%28A%29=2%2F3\" and \"tan%28B%29=1%2F4\",
\n" ); document.write( "and that those inverse functions are defined so that
\n" ); document.write( "\"A\" will be in quadrants I or II, and
\n" ); document.write( "\"B\" will be in quadrants I or IV.
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\n" ); document.write( "To calculate \"sin%28A-B%29\" we can use the trigonometric identity
\n" ); document.write( "\"sin%28A-B%29=sin%28A%29%2Acos%28B%29-sin%28B%29%2Acos%28A%29\"
\n" ); document.write( "So we need to find \"sin%28A%29\" , \"sin%28B%29\" , and \"cos%28B%29\" .
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\n" ); document.write( "In quadrants I and I \"sin%28A%29%3E0\", so
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\n" ); document.write( "Since \"tan%28B%29=1%2F4%3E0\" only hapens in quadrants I and III,
\n" ); document.write( "and the definition of the inverse tangent function says that \"B\" is in I or IV,
\n" ); document.write( "\"B\" is definitely in quadrant I, where sine and cosine are positive.
\n" ); document.write( "This is how angle \"B\" would look in a right triangle.
\n" ); document.write( " The hypotenuse of that right triangle measures \"sqrt%284%5E2%2B1%5E2%29=sqrt%2816%2B1%29=sqrt%2817%29\"
\n" ); document.write( "So, \"sin%28B%29=1%2Fsqrt%2817%29\" and \"cos%28B%29=4%2Fsqrt%2817%29\"
\n" ); document.write( "Substituting all the values found into \"sin%28A-B%29=sin%28A%29%2Acos%28B%29-sin%28B%29%2Acos%28A%29\" ,
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\n" ); document.write( "SInce that does not look elegant, and teachers do not like square roots in denominators, we multiply numerator and denominator times \"sqrt%2817%29\" to get
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