document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=871073>Question 871073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 23.	Robert can drive to work in 45 min, whereas if he decides to take the bus, the same trip takes 1 hr 15 min. If the average rate of the bus is 16 mph slower than his driving rate, how far does he travel to work? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #525306 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=525306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let driving speed  be x<BR>\n" );
document.write( "so distance traveled = 0.75x\r<BR>\n" );
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document.write( "bus speed = (x-16)<BR>\n" );
document.write( "time = 1.25 hours<BR>\n" );
document.write( "distance = 1.25(x-16)\r<BR>\n" );
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document.write( "distance is same\r<BR>\n" );
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document.write( "0.75x=1.25(x-16)\r<BR>\n" );
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document.write( "0.75x=1.25x-20\r<BR>\n" );
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document.write( "0.50x=20\r<BR>\n" );
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document.write( "x= 40 mph driving speed\r<BR>\n" );
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document.write( "bus speed = 40-16 = 24 mph </SPAN>\n" );
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